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find the quotient and remainder when x³ - 2x ² + 5x - 6  is divided by (x-3) using synthetic division


In the first row write the coefficients (with the sign) of  x³ - 2x ² + 5x - 6  inside (remember to put 0 for missing terms)
 from (x-3) you get 3 which you write outside (you would put -3 for (x+3))
carry the first coefficient  ['1' in this problem] to the third row, multiply it by the number on the side['3' in this problem] and write the product in the second row in the second column, add the corresponding numbers [-2 + 3] and write the sum [1] below it in the third row
multiply this sum  in the third row with the number on the side and  write the product [3] in the second row. add the corresponding numbers[5+3] and write the sum in the third row, multiply the sum  with the number on the side and write the product [24]  in the second column and then add
  the last number on the third row [18] is the remainder. the other numbers[1,1,8] are the coefficients of the quotient


quotient  = x² + x + 8
remainder = 18





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