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find the equation of the tangent
at t = pi/3 on the curve x=2cost , y = 3sint ---------------------------------------------- ----------------------------------------------- since the equation of the curve is in parametric form differentiate w.r.t. t find dy/dx using dy/dx = (dy/dt)/(dx/dt) substitute t=pi/3 in dy/dx to get the slope,m of the tangent use t = pi/3 in x=2cost , y = 3sint to get (x1,y1) the point of contact use (y-y1) = m(x-x1) to get the equation of the tangent answer and some steps are given below ================ * * ================ ![]() trig. formulae and certain standard ratios collection of revision questions |
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