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find the equation of the tangent at (1,1) on x²+y²+xy-3=0

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 tangent at (1,1) on x²+y²+xy-3=0
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take the equation of the curve  and differentitate w.r.t.x
using implicit differentiation and then extract dy/dx
evaluate it at (1,1) to get the slope 'm ' of the tangent
at (1,1) and then use the equation (y-y1)=m(x-x1)
answer and  some steps are given below
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(trig. formulae) 





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