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using mean value theorem show
that (b-a) / (1 +b²) < arctan(b) - arctan(a) < (b-a) / (1 +a²) if a<b also show that (pi/4) + (3/25) < arctan(4/3) < (pi/4) + (1/6) ---------------------------------------------- ----------------------------------------------- use f(x) = arctanx and use a<c<b to manipulate into the given expression for the second part since pi/4 = arctan(1) use a = 1 and b = 4/3, the 3/25 and 1/6 will come form (b-a) / (1 +b²) and (b-a) / (1 +a²) answer and some steps are given below ================ * * ================ ![]() ![]() other problems on applications of integration like area ,volume etc integration formulae problems on integration |
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