volume of the solid obtained by revolving the ellipse ( x² / a²) + ( y² / b²) = 1 about the x axis

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find the volume of the solid obtained by revolving the ellipse ( x² / a²) + ( y² / b²) = 1 about the x axis

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******* 1 1	volume of the solid obtained by revolving the ellipse ( x² / a²) + ( y² / b²) = 1 about the x axis ---------------------------------------------- ----------------------------------------------- extract y² from( x² / a²) + ( y² / b²) = 1 y² = ( b² / a²) [a² - x²] consider the solid obtained by revolving the portion of the area in the first quadrant required volume will be twice the volume of this solid. use the formula pi .∫ y²dx with suitable limits answer and some steps are given below ================ * * ================ other problems on integration integration formulae
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